Re: [問題] 指定group

看板R_Language作者 (天)時間10年前 (2015/08/16 08:51), 10年前編輯推噓4(4010)
留言14則, 1人參與, 最新討論串2/2 (看更多)
我不知道這樣有沒有快多少... 參考看看 library(data.table) # setnames library(plyr) # dlply, laply, mapvalues library(dplyr) # mutate, summarise, group_by library(magrittr) # %>%, %$% dt <- data.table( series = c(1,2,3,4,5,6,1,1,2,2,2,2,2), cate = c(2,3,4,2,2,5,1,2,2,3,4,4,4) ) ## method 1 (應該會較慢,而且程式比較醜) maptable = dlply(dt, .(series), table) %>% laply(function(x){ as.integer(colnames(x)[which.max(x)]) }) %>% cbind(as.integer(names(.)), .) dt2 = dt %>% mutate(cate = mapvalues(series, maptable[,1], maptable[,2])) ## method 2 -maptable = dt %>% group_by(series, cate) %>% summarise(n()) %>% group_by(series) %>% summarise(maxCate = max(cate)) dt2 = dt %>% mutate(cate = mapvalues(series, maptable$series, maptable$maxCate)) ## 把上面連在一起的版本 (沒有maptable這個暫存變數) dt2 = dt %>% group_by(series, cate) %>% summarise(n()) %>% group_by(series) %>% summarise(maxCate = max(cate)) %>% setnames("series", "maxSeries") %$% mutate(dt, cate = mapvalues(series, maxSeries, maxCate)) : 例如 : series cate : [1,] 1 2 : [2,] 2 3 : [3,] 3 4 : [4,] 4 2 : [5,] 5 2 : [6,] 6 5 : [7,] 1 1 : [8,] 1 2 : [9,] 2 2 : [10,] 2 3 : [11,] 2 4 : [12,] 2 4 : [13,] 2 4 : 在series中1出現三次,其cate分別為2,2,1 頻率最高的為2 : 想將所有series為1的族群 其cate欄位接指定為2 : 又例如 series中為2的族群 其cate 分別為 3,2,3,4,4,4 頻率最高的4 : 想將所有series為2的族群 其cate欄位皆指定為4 : 請問除了用for loop外有其他方法嗎? -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 123.205.27.107 ※ 文章網址: https://www.ptt.cc/bbs/R_Language/M.1439686290.A.B89.html

08/16 18:17, , 1F
謝謝你! 有快很多
08/16 18:17, 1F

08/16 18:18, , 2F
另外想請問如果是series中有missing data
08/16 18:18, 2F

08/16 18:19, , 3F
能針對missing data 保留其原本cate 值嗎
08/16 18:19, 3F
在maptable產生之後加上na.omit,然後加上控制項去控制NA不要覆蓋到原本的cate就好 PS: na.omit是把有包含NA的那一個ROW移除,是base的函數 dt <- data.table( series = c(1,2,3,4,5,6,1,1,2,2,2,2,2,NA,NA,NA), cate = c(2,3,4,2,2,5,1,2,2,3,4,4,4,3,3,1) ) dt2 = dt %>% group_by(series, cate) %>% summarise(n()) %>% group_by(series) %>% summarise(maxCate = max(cate)) %>% setnames("series", "maxSeries") %>% na.omit %$% mutate(dt, cate = ifelse(is.na(series), cate, mapvalues(series, maxSeries, maxCate))) # series cate # 1: 1 2 # 2: 2 4 # 3: 3 4 # 4: 4 2 # 5: 5 2 # 6: 6 5 # 7: 1 2 # 8: 1 2 # 9: 2 4 #10: 2 4 #11: 2 4 #12: 2 4 #13: 2 4 #14: NA 3 #15: NA 3 #16: NA 1

08/16 20:59, , 4F
謝謝! 了解了!
08/16 20:59, 4F

08/16 21:01, , 5F
但在實際執行時 會出現以下錯誤訊息
08/16 21:01, 5F

08/16 21:01, , 6F
Error in n() : This function should not be called
08/16 21:01, 6F

08/16 21:03, , 7F
directly
08/16 21:03, 7F

08/16 21:04, , 8F
查到是因為plyr 和dplyr皆有summarise功能
08/16 21:04, 8F
我的版本沒問題 你可以指定dplyr:::summarise

08/16 22:42, , 9F
謝謝, 但改完之後反而出現setnames的問題
08/16 22:42, 9F

08/16 22:42, , 10F
Error in setnames(., "series", "maxSeries") :
08/16 22:42, 10F

08/16 22:42, , 11F
Items of 'old' not found in column names: series
08/16 22:42, 11F

08/16 22:43, , 12F
請問你用的是哪一個版本呢? 謝謝
08/16 22:43, 12F
我都沒有問題... 我用的R: Revolution R Open 3.2.0 我的session information: > sessionInfo() R version 3.2.0 (2015-04-16) Platform: x86_64-w64-mingw32/x64 (64-bit) Running under: Windows 7 x64 (build 7601) Service Pack 1 locale: [1] LC_COLLATE=Chinese (Traditional)_Taiwan.950 [2] LC_CTYPE=Chinese (Traditional)_Taiwan.950 [3] LC_MONETARY=Chinese (Traditional)_Taiwan.950 [4] LC_NUMERIC=C [5] LC_TIME=Chinese (Traditional)_Taiwan.950 attached base packages: [1] stats graphics grDevices utils datasets methods base other attached packages: [1] magrittr_1.5 dplyr_0.4.2 plyr_1.8.3 data.table_1.9.4 loaded via a namespace (and not attached): [1] lazyeval_0.1.10 R6_2.0.1 assertthat_0.1 parallel_3.2.0 [5] DBI_0.3.1 tools_3.2.0 reshape2_1.4.1 Rcpp_0.12.0 [9] stringi_0.4-1 stringr_1.0.0 chron_2.3-45

08/17 00:14, , 13F
謝謝 我再試試看
08/17 00:14, 13F

08/17 00:15, , 14F
另外想請問如果series 和 cate 都是 character
08/17 00:15, 14F
這個應該不用改太多,你自己改一下就好了 ※ 編輯: celestialgod (123.205.27.107), 08/17/2015 09:23:53
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