Re: [問題] word count in files

看板Python作者Lucemia (生の直感、死の予感)時間17年前 (2008/02/25 10:18)推噓1(1推 0噓 1→)

留言2則, 1人參與討論串3/3 (看更多)

※ 引述《azulazure (獨在異鄉為異客)》之銘言： : I'm trying to write a command that print the largest file in the current : working directory. I'm able to print all the files and their wordcount, : but I don't know how to print just the largest one. Two methods. First, just save each file's filename and wordcount, then use max or sort to find out the largest one. It should looks like that .. countcache = [] for file .. # you loop for each file ... coundcache += [(file,wordcount)] ... countcache.sort(key = lambda i: i[1]) print countcache[-1] Second, use a variable to save the biggest file and wordcount and update them with your scanning progress. It should looks like that .. filecache = "" wordcountcache = -1 for file .... if wordcount > wordcountcache: filecache = file wordcountcache = wordcount print filecache, wordcountcache btw. in fact your question is about programming, not about python. : Here's what I have: : import os : cwd = os.getcwd() : for file in os.listdir(cwd): : if os.path.isdir(file) == False: : if file[0] != '.': : word = open(file, 'r').read().split() : wordcount = len(word) : I tried to use range function to do the work, but it didn't work. : I wrote like this (following what I had above): : for x in range(wordcount): : if x in range(wordcount - 1) == False: : print x : When I ran it, nothing happened. Can anyone tell me what's wrong? : Or is there a better way to do it? : My logic is that if the number is larger than the max number -1, : it should be the largest number. : Thanks in advance for any help! -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.110.216.36