[問題] airtime問題

看板java作者 (...)時間19年前 (2006/05/09 20:27), 編輯推噓0(000)
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我用書中的範例在WTK裡run..確出現以下訊息 ConnectorDemo wants to send and receive data using the network. this will use airtime and may result in charges. is it ok to use airtime? 這要怎麼解決阿 ?? 範例如下: public ConnectorDemo() // 屬性、元件、初值設定(初始化) { display = Display.getDisplay(this); exitCommand = new Command("離開", Command.EXIT, 1); connCommand = new Command("連線", Command.OK, 1); } public void startApp() // 程式進入點 { showForm =new Form("HTTP 連線"); showForm.append(new String("請按「連線」鍵") ); showForm.addCommand(exitCommand); showForm.addCommand(connCommand); showForm.setCommandListener(this); display.setCurrent(showForm); } public void pauseApp() { } public void destroyApp(boolean unconditional) { } public void commandAction(Command c, Displayable s) // 各事件處理函數 { if(c==connCommand) { String showStr=""; HttpConnection httpConn = null; try // 開啟連線 { httpConn = (HttpConnection)Connector.open("http://127.0.0.1:8080/index.htm"); if( httpConn.getResponseCode() == HttpConnection.HTTP_OK) showStr = "連線成功!"; else showStr = "連線失敗!"; } catch(Exception O) { showStr = O.getMessage(); } try // 關閉連線 { if(httpConn != null) httpConn.close(); } catch(Exception O) { showStr = O.getMessage(); } // 將連線狀態顯示在 Alert 物件上 Alert alert = new Alert("連線狀態", showStr, null, AlertType.INFO); alert.setTimeout( Alert.FOREVER ); display.setCurrent( alert ); } if(c==exitCommand) { destroyApp(false); notifyDestroyed(); } } } -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.223.212.177
文章代碼(AID): #14O8h2Uo (java)
文章代碼(AID): #14O8h2Uo (java)