[問題] 也是另一個比對問題?
若我知道 以下這些條件
ACT with PTN PTN 與 class2:ACT PTN PTN
ACT of PTN with PTN and PTN 與 class2:ACT PTN PTN
ACT PTN and PTN 與 class2:ACT PTN PTN
with PTN to ACT PTN . 與 class1:PTN ACT PTN
PTN and PTN ACT with and PTN 與 class1:PTN ACT PTN
. PTN ACT with PTN in 與 class1:PTN ACT PTN
ACT of PTN PTN ACT 與 class3:PTN PTN ACT
PTN in PTN ACT of PTN ACT by 與 class3:PTN PTN ACT
ACT with PTN PTN ACT 與 class3:PTN PTN ACT
例子一:
ACT with PTN PTN 想取到下面()內的字
==> () ACT (with) PTN () PTN ()
即我想取得 class2:ACT PTN PTN 的前後與中間兩個範圍內的字,若沒有字則以空白代替
==> ($left, $middle1, $middle2, $right) = ("","with","","");
例子二:
with PTN to ACT PTN . 與 class1:PTN ACT PTN
==> (with) PTN (to) ACT () PTN (.)
==> ($left, $middle1, $middle2, $right) = ("with","to","",".");
例子三:
ACT of PTN PTN ACT class3:PTN PTN ACT
==>(ACT of) PTN () PTN () ACT ()
==> ($left, $middle1, $middle2, $right) = ("ACT of","","","");
請問有人可以解決或回答嗎^^?感謝:)
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