[問題] 也是另一個比對問題?

看板Perl作者 (開心)時間18年前 (2007/04/09 12:40), 編輯推噓0(000)
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若我知道 以下這些條件 ACT with PTN PTN        與 class2:ACT PTN PTN ACT of PTN with PTN and PTN 與 class2:ACT PTN PTN ACT PTN and PTN        與 class2:ACT PTN PTN with PTN to ACT PTN . 與 class1:PTN ACT PTN PTN and PTN ACT with and PTN  與 class1:PTN ACT PTN . PTN ACT with PTN in 與 class1:PTN ACT PTN ACT of PTN PTN ACT 與 class3:PTN PTN ACT PTN in PTN ACT of PTN ACT by 與 class3:PTN PTN ACT ACT with PTN PTN ACT 與 class3:PTN PTN ACT 例子一: ACT with PTN PTN 想取到下面()內的字 ==> () ACT (with) PTN () PTN () 即我想取得 class2:ACT PTN PTN前後與中間兩個範圍內的字若沒有字則以空白代替 ==> ($left, $middle1, $middle2, $right) = ("","with","",""); 例子二: with PTN to ACT PTN . 與 class1:PTN ACT PTN ==> (with) PTN (to) ACT () PTN (.) ==> ($left, $middle1, $middle2, $right) = ("with","to","","."); 例子三: ACT of PTN PTN ACT class3:PTN PTN ACT ==>(ACT of) PTN () PTN () ACT () ==> ($left, $middle1, $middle2, $right) = ("ACT of","","",""); 請問有人可以解決或回答嗎^^?感謝:) -- -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.116.165.150
文章代碼(AID): #166SEWWz (Perl)
文章代碼(AID): #166SEWWz (Perl)