Re: [請益] PHP如何接收POST過來的XML DOM ？
為什麼只能接收raw post data 呢？
為什麼 $_POST 就不行了呢？
想破頭了啊!!!...
-----------------domTest.html-------------------------------------
<html>
<head>
<meta http-equiv="Content-Type" content="text/html;charset=Big5">
<title>送出 XML DOM 物件</title>
<body>
<script language="JavaScript">
var strXML = "<book>";
strXML = strXML + "<code>F6476</code><booktitle>";
strXML = strXML + "ASP.NET 2.0網頁製作徹底研究</booktitle>";
strXML = strXML + "<author>陳會安</author>";
strXML = strXML + "<price>660</price>";
strXML = strXML + "</book>";
var xmlDom = new ActiveXObject("MSXML2.DOMDocument.6.0");
xmlDom.async = "false";
xmlDom.loadXML(strXML);
var httpRequest = new ActiveXObject("MSXML2.XMLHTTP.6.0");
httpRequest.open("POST", "domTest.php", false);
httpRequest.send(xmlDom);
var str = "伺服器狀態: " + httpRequest.status + " - ";
str = str + httpRequest.statusText;
document.write(str + "<br>");
xmlResult = httpRequest.responseText;
document.write(xmlResult);
</script>
</body>
</html>
-----------------domTest.php------------------------------------
<?php
$a = $_POST;
var_dump($a);
?>
-------------
傳回來的結果是空的陣列：array(0){}
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