Re: [問題] 產生random vector已回收
※ 引述《microball (無華之果)》之銘言：
不好意思, 我依然看不懂你再說什麼,
建議你在寫出你的 code 之前, 用幾句話去描述一下你的演算法,
不然很難閱讀你的程式. (Degub is always the hard work.)
: N = 1000;
: aG = 2*pi.*rand(N,1);
: bG = pi.*rand(N,1);
: cG = 2*pi.*rand(N,1);
You generate 3 random angles ?
: RandR = zeros(N,3);
: z1 = [1 0 0];
: for (j = 1:N)
: a = aG(j);
: b = bG(j);
: c = cG(j);
: Ea = [cos(a) sin(a) 0; -sin(a) cos(a) 0; 0 0 1];
: Eb = [1 0 0; 0 cos(b) sin(b); 0 -sin(b) cos(b)];
: Ec = [cos(c) sin(c) 0; -sin(c) cos(c) 0; 0 0 1];
: RandR(j,:) = (Ec*Eb*Ea*(z1'))';
: end
: plot3(RandR(:,1),RandR(:,2),RandR(:,3),'.')
It means 3 rotation matrix. Q(x,y) and Q(y,x), Q(x,y).
(Hope I got it right?)
Here is the question:
1. Why you need 3 rotation ? It's a 2D random-ness.
2. If you only do for Eb*Ea*(Z1). it's exaxtly the answer you gave before,
which can be proved as wrong.
How do you explain yourself, convince others that's a correct one ?
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