Re: [問題] AUTOCAD怎麼繪出方程式曲線?
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; this is a comment
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this is the block comment
can over server lines
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(textscr)
; we will plot a sine- curve, from 0 - 360, t1 - t2
; step dt
; dt= (t2 - t1)/no
; no= ?
(setq no (getint "Please input a number(100 - 300) for test: "))
(setq t1 0.0 t2 360.0)
(setq dt (/ (- t2 t1) no))
(command "blipmode" "off")
(setvar "cmdecho" 0)
(graphscr)
(command "PLine")
; for tt= t1 to t2 step dt do ...
(setq t2 (+ t2 (/ dt 10.0)))
(setq tt t1)
(while (＜＝ tt t2)
(setq x (* (/ tt 180.0) pi))
(setq y (sin x))
(setq p1 (list x y))
(command p1)
(setq tt (+ tt dt))
); end of while()
(command "")
(princ); end of the file
※ 引述《cino13 (阿升)》之銘言：
: 請問板上各位
: 如果我有一曲線方程式 例如 y=ax+b 0<= y,x<=1 之類
: 怎樣繪出此曲線方程式圖形??
--
※ 發信站: 批踢踢實業坊(ptt.cc)
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