Re: [問題] 九九乘法表不用迴圈是叫我直接從1列到81?
看板C_and_CPP (C/C++)作者CindyLinz (Cindy Wang)時間6年前 (2018/07/18 03:16)推噓4(4推 0噓 5→)留言9則, 6人參與討論串9/29 (看更多)
: 九九乘法表用兩個或一個迴圈來做我都會
: 但不用迴圈叫我列九九乘法表是哪招？
: 難道是要我直接從1*1列到9*9嗎？
: 還是其實有妙招？
: 說實在我真想不到不用迴圈就能簡單列出九九乘法表的方法了
這一個版本.. 我只能確定 it works on my machine....XD (x86_64)
99.c:
#include <stdio.h>
long long salon(long long hair, int i){
if( i < 1 ) hair = 2[&hair];
if( i < 81 ) 2[&hair] = hair;
return hair;
}
int main(){
int i = -1;
long long hair = salon(hair, ++i);
printf("%d x %d = %2d %c", i/9+1, i%9+1, (i/9+1) * (i%9+1), 32-22*!(i%9-8));
hair = salon(hair, ++i);
return 0;
}
$ gcc -O0 -o 99 99.c
$ ./99
1 x 1 = 1 1 x 2 = 2 1 x 3 = 3 1 x 4 = 4 1 x 5 = 5 1 x 6 = 6 1 x 7 = 7 1 x 8 = 8 1 x 9 = 9
2 x 1 = 2 2 x 2 = 4 2 x 3 = 6 2 x 4 = 8 2 x 5 = 10 2 x 6 = 12 2 x 7 = 14 2 x 8 = 16 2 x 9 = 18
3 x 1 = 3 3 x 2 = 6 3 x 3 = 9 3 x 4 = 12 3 x 5 = 15 3 x 6 = 18 3 x 7 = 21 3 x 8 = 24 3 x 9 = 27
4 x 1 = 4 4 x 2 = 8 4 x 3 = 12 4 x 4 = 16 4 x 5 = 20 4 x 6 = 24 4 x 7 = 28 4 x 8 = 32 4 x 9 = 36
5 x 1 = 5 5 x 2 = 10 5 x 3 = 15 5 x 4 = 20 5 x 5 = 25 5 x 6 = 30 5 x 7 = 35 5 x 8 = 40 5 x 9 = 45
6 x 1 = 6 6 x 2 = 12 6 x 3 = 18 6 x 4 = 24 6 x 5 = 30 6 x 6 = 36 6 x 7 = 42 6 x 8 = 48 6 x 9 = 54
7 x 1 = 7 7 x 2 = 14 7 x 3 = 21 7 x 4 = 28 7 x 5 = 35 7 x 6 = 42 7 x 7 = 49 7 x 8 = 56 7 x 9 = 63
8 x 1 = 8 8 x 2 = 16 8 x 3 = 24 8 x 4 = 32 8 x 5 = 40 8 x 6 = 48 8 x 7 = 56 8 x 8 = 64 8 x 9 = 72
9 x 1 = 9 9 x 2 = 18 9 x 3 = 27 9 x 4 = 36 9 x 5 = 45 9 x 6 = 54 9 x 7 = 63 9 x 8 = 72 9 x 9 = 81
--
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