[問題] 計算以999作為結束的序列平均&總和
Question:能反覆輸入一個整數值num，直到輸入的num值為999則停止，計數不包含999
在內，輸入值共有幾個?並計算這些輸入值得總合以及平均(實數)
省略include
int main()
{
int num,a=0,sum=0;
cout<<"\n輸入一個整數值";
cin>>num;
while(num!=999)
{
if(num%1==0)
a++;
sum+=num;
}
cout<<"輸入一個整數";
cin>>num;
}
cout<<"\n不包含999在內，輸入值共有"<<a<<"個";
system("pause");
return 0;
}
總合還有平均怎麼算呢
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 125.224.201.37
→
07/29 17:48, , 1F
07/29 17:48, 1F
→
07/29 17:51, , 2F
07/29 17:51, 2F
→
07/29 17:54, , 3F
07/29 17:54, 3F
→
07/29 17:54, , 4F
07/29 17:54, 4F
推
07/29 17:54, , 5F
07/29 17:54, 5F
→
07/29 18:04, , 6F
07/29 18:04, 6F
→
07/29 18:04, , 7F
07/29 18:04, 7F
推
07/29 18:05, , 8F
07/29 18:05, 8F
→
07/29 18:06, , 9F
07/29 18:06, 9F
→
07/29 18:07, , 10F
07/29 18:07, 10F
→
07/29 18:13, , 11F
07/29 18:13, 11F
→
07/29 18:28, , 12F
07/29 18:28, 12F
推
07/29 18:37, , 13F
07/29 18:37, 13F
→
07/29 18:37, , 14F
07/29 18:37, 14F
→
07/29 18:39, , 15F
07/29 18:39, 15F
→
07/29 18:41, , 16F
07/29 18:41, 16F
→
07/29 18:49, , 17F
07/29 18:49, 17F
→
07/29 19:27, , 18F
07/29 19:27, 18F
推
07/29 20:33, , 19F
07/29 20:33, 19F
→
07/29 22:04, , 20F
07/29 22:04, 20F
→
07/29 22:06, , 21F
07/29 22:06, 21F
→
07/29 22:06, , 22F
07/29 22:06, 22F
→
07/29 22:07, , 23F
07/29 22:07, 23F
→
07/29 22:15, , 24F
07/29 22:15, 24F
→
07/29 22:16, , 25F
07/29 22:16, 25F
→
07/29 22:22, , 26F
07/29 22:22, 26F
推
07/30 02:47, , 27F
07/30 02:47, 27F
C_and_CPP 近期熱門文章
PTT數位生活區 即時熱門文章