[問題] 不好意思麻煩大家一下

看板C_and_CPP (C/C++)作者carlos761017 (異形)時間16年前 (2009/04/13 14:07)推噓1(1推 0噓 3→)

留言4則, 3人參與討論串1/2 (看更多)

其實我正在寫FFT的演算法是用cooley-tukey的algorithm寫的可是卻出現了兩個問題 Q1:compile完的時候程式說expect '}'at the end of input 可是我卻找不出我是哪邊少打了'}' 請大家幫我看看好嗎? Q2:其實我也有就在結尾再補一個'}'可是她compile又說 [Linker error] Undefined reference to 'Winmain@16' Id returned 1 exit status 我就不懂這是什麼意思了就這兩個問題~ 麻煩大家了~~~ 謝謝~~ 以下是我的CODE #include <stdio.h> #include <stdlib.h> #include <math.h> #include <cmath> #define i pow(-1,1/2) #define pi 3.14159256 #define N 8 #define r 3 #define NU1 r-1 void FFT() { int N2=N/2; int bitn=N-1; int bitk=N-1; int l=r; int n[r],k[r]; float rex[N][l],imx[N][l]; float rey[N],imy[N]; float p=0,p1=0; //power of W double fcos,fsin; ///counter int q=0,a=0,b=0,c=0,d=0; /* 給初始值 */ for (d=0; d<r; d++) { n[d]=0; k[d]=0; } for (a=0; a<N; a++) { for (l=0; l<r; l++) { rex[a][l]=0; imx[a][l]=0; } } for (b=0; b<N; b++) { rey[b]=0; imy[b]=0; } /* 輸入data */ FILE * fp; fp = fopen("fft_x.DAT","r"); for (bitk=0; bitk<=N-1; bitk++) { //x[k]=(Redata[k],Imdata[k]); fscanf (fp, "%f", &rex[bitk][0]); imx[bitk][0]=0; printf("(%f,%f) \n",rex[bitk][0],imx[bitk][0]); } //n and k decompose for (l=1; l<=r; l++) { printf("L=%d \n",l); for(bitn=0,bitk=0; bitn<N||bitk<N; bitn++,bitk++) { for (q=0; q<r; q++) { n[r-q]=bitn%(int)pow(2,r-q)/(int)pow(2,q);//bit reverse //k[r-r+q]=bitk%pow(2,r-q)/pow(2,q); //FFT algorithm for (k[r-l]=0; k[r-l]<2; k[r-l]++) { for(c=1; c<=l; c++)p1=p1+n[c-1]*pow(2,c-1); p=pow(2,r-l)*k[r-l]*p1; fcos=acos(2*pi*p/N); fsin=asin(2*pi*p/N); if(bitk<N2 && k[r-1]==0) { rex[bitk][l]=rex[bitk][l]+rex[bitk][l-1]*fcos-imx[bitk][l-1]*fsin; imx[bitk][l]=imx[bitk][l]+rex[bitk][l-1]*fsin+imx[bitk][l-1]*fcos; } else if(bitk<N2 && k[r-1]==1) { rex[bitk][l]=rex[bitk][l]+rex[bitk+N2][l-1]*fcos-imx[bitk+N2][l-1]*fsin; imx[bitk][l]=imx[bitk][l]+rex[bitk+N2][l-1]*fsin+imx[bitk+N2][l-1]*fcos; } else if(bitk>=N2 && k[r-1]==0) { rex[bitk][l]=rex[bitk][l]+rex[bitk][l-1]*fcos-imx[bitk][l-1]*fsin; imx[bitk][l]=imx[bitk][l]+rex[bitk][l-1]*fsin+imx[bitk][l-1]*fcos; } else { rex[bitk][l]=rex[bitk][l]+rex[bitk-N2][l-1]*fcos-imx[bitk-N2][l-1]*fsin; imx[bitk][l]=imx[bitk][l]+rex[bitk-N2][l-1]*fsin+imx[bitk-N2][l-1]*fcos; } } printf("x%d(%d)=(%f,%f) \n",l,bitk,rex[bitk][l],imx[bitk][l]); } N2=N2/2; printf("\n"); } system("PAUSE"); } -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 218.168.193.83

[問題] 不好意思 麻煩大家一下

[問題] 不好意思麻煩大家一下