$firm_id = $_POST["q1_01_02"];
$password = $_POST["password"];
$project_rows = $_POST["project_rows"];
$name_chinese = $_POST["q1_01_01"];
$boss = $_POST["q1_01_03"];
$contact = $_POST["q1_01_04"];
$email = $_POST["q1_01_05"];
$phone = $_POST["q1_01_06"];
$fax = $_POST["q1_01_07"];
$address1 = $_POST["q1_01_08"];
$address2 = $_POST["q1_01_09"];
$website = $_POST["q1_01_10"];
$year_founded = $_POST["q1_01_11"];
$stock = $_POST["q1_01_12a"];
$stockstatus = $_POST["q1_01_12b"];
$stock_year1 = $_POST["q1_01_12b1"];
$stock_year2 = $_POST["q1_01_12b2"];
$sql = "UPDATE firm SET name_chinese='$name_chinese', boss='$boss',
contact='$contact', email='$email', phone='$phone', fax='$fax',
address1='$address1', address2='$address2', website='$website',
year_founded='$year_founded', stock='$stock', stockstatus='$stockstatus',
stock_year1='$stock_year1', stock_year2='$stock_year2' WHERE
firm_id='$firm_id'";
mysql_query($sql, $link_ID);
資料庫那邊也設好了
到底是哪裡出了問題
我記得有檢測這個變數是否有傳回資料到資料庫的指令
acho什麼的
感謝
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05/05 15:52, , 1F
05/05 15:52, 1F
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