[問題] C++新手之學校作業 程式碼露露登 有辦法縮短嗎?
這學期才有的C++課程
老師出了一個作業題目
-------題目------------------
三種水果: 每一種水果有一個條碼編號. 利用條碼編號來分辨價錢.
由使用者輸入條碼編號及重量, 將所有水果的總價計算出來.
水果條碼(Barcode): 水果單價
AppleBR = 234567 100 BananaBR = 563453 35 PapayaBR = 734523 45
每樣水果買超過 10 公斤 打8折. 老主顧一律打95折.
利用 printf("\nInput BarCode: "); scanf("%d", &BarCode); // 取得條碼
printf("\nInput Fruit Weight: "); scanf("%lf", &Weight); // 取得重量
三種水果都要買.
--------------------------------------
以下程式碼有辦法縮短嗎@@?
寄個站內信 感恩阿里阿豆
------以下是新手我打的程式碼有點長--------
#include "stdafx.h"
#define _New 1
#define _Old 2
#define _New_apple 1
#define _New_banana 2
#define _New_papaya 3
#define _Old_apple 4
#define _Old_banana 5
#define _Old_papaya 6
int _tmain(int argc, _TCHAR* argv[])
{
int Fruit,Name;
double Price ;
double Weight =0 ;
double TotalPrice =0 ;
int Number =0,Count=0;
printf("你想要買幾種水果? ");
scanf("%d", &Number);
Count = 0;
while(Count < Number)
{
printf(" Please Input Name(New=1,Old=2) :");
scanf("%d", &Name);
if(Name == 1)
{
printf(" Please Input Fruit(apple=1,banana=2,papaya=3) :");
scanf("%d", &Fruit);
}
else
printf(" Please Input Fruit(apple=4,banana=5,papaya=6) :");
scanf("%d", &Fruit);
printf(" Please Input Weight:");
scanf("%lf", &Weight);
if(Weight > 10.0)
{
switch(Fruit)
{
case _New_apple:
Price = 80 * Weight;
break;
case _New_banana:
Price = 28 * Weight;
break;
case _New_papaya :
Price = 36 * Weight;
break;
case _Old_apple:
Price = 80 * Weight;
break;
case _Old_banana:
Price = 28 * Weight;
break;
case _Old_papaya :
Price = 36 * Weight;
break;
}
}
else
switch(Name)
{
case _New:
switch(Fruit)
{
case _New_apple:
{
Price = 100 * Weight;
}
break;
case _New_banana:
Price = 35 * Weight ;
break;
case _New_papaya :
Price = 45 * Weight;
break;
}
case _Old:
switch(Fruit)
{
case _Old_apple:
{
Price = 95 * Weight;
}
break;
case _Old_banana:
Price = 33.25 * Weight;
break;
case _Old_papaya :
Price = 42.75 * Weight ;
break;
}
break;
}
TotalPrice += Price ;
Count ++;
}
return 0;
}
--
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