[問題] 我應該直接問音樂遊戲的計時器該怎麼做 QQ

看板C_and_CPP (C/C++)作者crazytea (............)時間16年前 (2009/04/25 21:18)推噓1(1推 0噓 10→)

留言11則, 3人參與討論串1/1

其實前面的碼表問題本來是希望能夠自己解決，沒想到問的詞不達意還無法解決問題　囧所以就直接問了！音樂遊戲一定要藉由精準的時間判定來播放botton 該在幾秒案就該在幾秒按雖然拍子跟秒數之間有公式可以算（bpm）例如：150 bpm （即 1 分鐘　150拍）但是算到後來一拍的時間也是幾百 ms 要如何計算從音樂開始播放後每隔固定時間（拍子）播放botton 是我現在的瓶頸～～我有下載跳舞機模擬器( stepMania ) 的原始碼來看, 但是由於程式過於龐大，目前只針對timeGetTime()尋找整個專案找到相關程式碼如下： static bool g_bTimerInitialized; static DWORD g_iStartTime; static void InitTimer() { if( g_bTimerInitialized ) return; g_bTimerInitialized = true; timeBeginPeriod( 1 ); g_iStartTime = timeGetTime(); } int64_t ArchHooks::GetMicrosecondsSinceStart( bool bAccurate ) { if( !g_bTimerInitialized ) InitTimer(); int64_t ret = (timeGetTime() - g_iStartTime) * int64_t(1000); if( bAccurate ) { ret = FixupTimeIfLooped( ret ); ret = FixupTimeIfBackwards( ret ); } return ret; } uint64_t ArchHooks::FixupTimeIfLooped( uint64_t usecs ) { static uint64_t last = 0; static uint64_t offset_us = 0; /* The time has wrapped if the last time was very high and the current time is very low. */ const uint64_t i32BitMaxMs = uint64_t(1) << 32; const uint64_t i32BitMaxUs = i32BitMaxMs*1000; const uint64_t one_day = uint64_t(24*60*60)*1000000; if( last > (i32BitMaxUs-one_day) && usecs < one_day ) offset_us += i32BitMaxUs; last = usecs; return usecs + offset_us; } uint64_t ArchHooks::FixupTimeIfBackwards( uint64_t usecs ) { static uint64_t last = 0; static uint64_t offset_us = 0; if( usecs < last ) { /* The time has moved backwards. Increase the offset by the amount we moved. */ offset_us += last - usecs; } last = usecs; return usecs + offset_us; } 還是搞不懂他在幹啥？或是有更好的方法嗎？ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 192.192.154.40