[問題] learn ruby the hard way 41
想請教關於 learn ruby the hard way Exercise41 的一段程式碼
http://learnrubythehardway.org/book/ex41.html
在oop_test.rb這個檔案裡面有一段
從
50 param_names = craft_params(rand_words, snippet, /@@@/)
跳到
36 def craft_params(rand_words, snippet, pattern)
37 names = (0...snippet.scan(pattern).length).map do
38 param_count = rand(3) + 1
39 params = (0...param_count).map {|x| rand_words.pop() }
40 params.join(', ')
41 end
42
43 return names * 2
44 end
這段看不太懂，
我嘗試 puts (0...snippet.scan(pattern).length).map
但是印出來的結果是 #<Enumerator:0x000000028ee138> <==??
接下來我嘗試
puts (0...3).map
結果是只出現一個 #<Enumerator:0x000000028653b0>
而不是
#<Enumerator:0x000...>
#<Enumerator:0x000...>
#<Enumerator:0x000...>
這樣的話假設我的param_count = 3
那39行怎麼知道要pop三個word出來呢？
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