[請益] 新手http response無法顯示求解

看板PHP作者biggood20708 (Neoli)時間8年前 (2017/01/20 11:09)推噓3(3推 0噓 4→)

留言7則, 4人參與討論串1/1

<html> <head> <meta http-equiv="content-type" content = "text/html;charset=utf-8"> <script src = "utility.js" type = "text/javascript"></script> <script type = "text/javascript"> var XHR = null; function startRequest() { XHR = createXMLHttpRequest(); XHR.open("GET","poetry.txt",true); XHR.onreadystatechange=handleStateChange; XHR.send(null); } function handleStateChange() { if(XHR.readyState == 4) { if(XHR.status == 200) document.getElementByid("span1").innerHTML=XHR.responseText; else window.alert("error!"); } } </script> </head> <body> <form id = "form1"> <input id = "button1" type = "button" value = "顯示" onclick="startRequest()"> <br><br><span id = "span1"></span> </form> </body> </html> 基本上是照參考書上打的，但是button按了就一直顯示不出來看了半天也不知道哪裡出錯，poetry.txt也建立了裡面也有內容希望各位大大給新手一點幫助 -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 220.135.159.117 ※ 文章網址: https://www.ptt.cc/bbs/PHP/M.1484881760.A.70B.html

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anest

01/20 11:27, , 1^F

01/20 11:27, 1^F

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mimikillua

01/20 11:37, , 2^F

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wotupset

01/20 13:46, , 3^F

01/20 13:46, 3^F

感謝大家幫忙，不過更改過後還是無法顯示我在poetry.txt中的文字請問還有哪裡出問題呢？更改過後的程式碼如下 https://goo.gl/B9unxk ※ 編輯: biggood20708 (220.135.159.117), 01/20/2017 18:13:22