[請益] SQL指令不過 undefined variable
if(is_uploaded_file($_FILES['ul']['tmp_name'])){
if(!is_dir($c_id) || !is_writeable($c_id))
die("目錄不存在或無法寫入");
$File_Extension = explode(".", $_FILES['ul']['name']);
$File_Extension = $File_Extension[count($File_Extension)-1];
$ServerFilename =$a_id . "_" . $year . "_" . $j_id . "_" .
$title . "." . $File_Extension;
move_uploaded_file($_FILES['ul']['tmp_name'] , $c_id . "/" .
$ServerFilename );
echo "Upload OK！ ";
$SQLStr = "INSERT INTO paper ( j_id, year, vol, no, title,
a_id, abstract, keyword, c_id, ul, time) " . "VALUES('$j_id', '$year',
'$vol', '$no', '$title', '$a_id', '$abstract', '$keyword', '$c_id',
'$ServerFilename', '$time')";
}
// 新增文獻資料
// 依執行查詢的結果, 指定要顯示的訊息
if(db_query($SQLStr))
$message = "已新增一筆新的文獻資料！";
else
$message = "新增文獻資料失敗！";
}
SQLStr沒出來..
徵求強者幫我解惑..感謝
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◆ From: 118.232.184.83
※ 編輯: catxii 來自: 118.232.184.83 (11/16 22:08)
※ 編輯: catxii 來自: 118.232.184.83 (11/16 22:09)
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