[討論] solve方程組
請問一下
我今天有3個未知數a,b,c待求定
亦有三個方程式eq1,eq2,eq3
我使用symbolic進行解方程組
為什麼每個解都是8x1 syms呢
小弟數學不好請見諒
code如下
syms a b c
eq1=(1+a^2-b^2-c^2)/(1+a^2+b^2+c^2)-0.99768250;
eq2=(1-a^2+b^2-c^2)/(1+a^2+b^2+c^2)-0.75500072;
eq3=(1-a^2-b^2+c^2)/(1+a^2+b^2+c^2)-0.75731587;
[a,b,c]=solve(eq1,eq2,eq3,'a','b','c')
------
結果如下
a =
-8638450155872395594504574183690^(1/2)/7903815296897390
8638450155872395594504574183690^(1/2)/7903815296897390
-8638450155872395594504574183690^(1/2)/7903815296897390
8638450155872395594504574183690^(1/2)/7903815296897390
-8638450155872395594504574183690^(1/2)/7903815296897390
8638450155872395594504574183690^(1/2)/7903815296897390
-8638450155872395594504574183690^(1/2)/7903815296897390
8638450155872395594504574183690^(1/2)/7903815296897390
b =
-10456213264794931385910795^(1/2)/3951907648448695
-10456213264794931385910795^(1/2)/3951907648448695
10456213264794931385910795^(1/2)/3951907648448695
10456213264794931385910795^(1/2)/3951907648448695
-10456213264794931385910795^(1/2)/3951907648448695
-10456213264794931385910795^(1/2)/3951907648448695
10456213264794931385910795^(1/2)/3951907648448695
10456213264794931385910795^(1/2)/395190764844869
c =
-82451023629991619035344171910^(1/2)/7903815296897390
-82451023629991619035344171910^(1/2)/7903815296897390
-82451023629991619035344171910^(1/2)/7903815296897390
-82451023629991619035344171910^(1/2)/7903815296897390
82451023629991619035344171910^(1/2)/7903815296897390
82451023629991619035344171910^(1/2)/7903815296897390
82451023629991619035344171910^(1/2)/7903815296897390
82451023629991619035344171910^(1/2)/7903815296897390
還請板上高手指點迷津
是我用的function有錯嗎
還是正解就是這樣= _=
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