[討論] 日期計算防呆

看板MATLAB作者carmelono15 (阿淦)時間13年前 (2012/11/07 03:47)推噓0(0推 0噓 5→)

留言5則, 2人參與討論串1/1

小弟我這學期修了系上開的MATLAB 是第一次接觸這軟體最近上到了關於for跟while的迴圈課本上有個例題是關於日期的計算簡單講就是使用者輸入一組年月日然後程式會告訴你你輸入的日期是當年度的第幾天例如:輸入1/10/2012 程式就會告訴你是2012的第10天然後我反正閒閒回家都會照著課本把課本的程式碼打進去matlab當作練習就在run的時候我發現如果輸入15/33/99999 程式還是會告訴我那天是當年度的第398天囧但是沒有15月也沒有33號啊翻了翻後面也沒有說要怎麼防呆這章節是在說迴圈所以我在想是不是要在哪個地方加個for或while loop進去就可解決這問題了有高手可以提點我嗎我貼一下程式碼 clear all;close all;clc; % get day, month, and year to convert disp('This program calculates the day of year given the special date.'); month = input('Enter specified month (1-12): '); day = input('Enter specified day (1-31): '); year = input('Enter specified year (yyyy): '); % check for leap year, and add extra day if necessary if mod(year,400) == 0 leap_day = 1; % years divisible by 400 are leap years elseif mod(year,100) == 0 leap_day = 0; % other centuries are not leap years elseif mod(year,4) == 0 leap_day = 1; % otherwise every 4th year is a leap day else leap_day = 0; % other years are not leap years end % calculate day of year by adding current day to the % days in previous months. day_of_year = day; for ii = 1:month-1 % add days in months from January to last month switch (ii) case{1,3,5,7,8,10,12}, day_of_year = day_of_year + 31; case{4,6,9,11}, day_of_year = day_of_year + 30; case 2, day_of_year = day_of_year + 28 +leap_day; end end % tell user fprintf('The date %2d/%2d/%4d is day of year %d.\n', ... month,day,year,day_of_year); -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.32.190.58