[請益] ansys 外力位置改變迴圈

看板Cad_Cae (電腦輔助設計)作者tgozero (tgozero)時間12年前 (2014/05/05 21:45)推噓1(1推 0噓 0→)

留言1則, 1人參與討論串1/1

第一次發文問問題我在ansys workbench 內想寫個command 希望外力能夠在do 迴圈下然後每一次得到一個不同的轉角變位程式碼如下但是我希望每一次do迴圈都只有一組新的力量所以上一次的外力在算完結果之後要清掉想請問大家該怎麼做會比較好 *DIM,knopen,ARRAY,16,1 *set,knopen(1),node (0.073,1.499,0.075) *set,knopen(2),node (0.565,1.499,0.075) *set,knopen(3),node (1.057,1.499,0.075) *set,knopen(4),node (1.549,1.499,0.075) *set,knopen(5),node (0.073,1.007,0.075) *set,knopen(6),node (0.565,1.007,0.075) *set,knopen(7),node (1.057,1.007,0.075) *set,knopen(8),node (1.549,1.007,0.075) *set,knopen(9),node (0.073,0.515,0.075) *set,knopen(10),node (0.565,0.515,0.075) *set,knopen(11),node (1.057,0.515,0.075) *set,knopen(12),node (1.549,0.515,0.075) *set,knopen(13),node (0.073,0.023,0.075) *set,knopen(14),node (0.565,0.023,0.075) *set,knopen(15),node (1.057,0.023,0.075) *set,knopen(16),node (1.549,0.023,0.075) *DO,ii,3,3 /SOL f,knopen(ii),MX,1 f,knopen(ii+1),MX,1 f,knopen(ii+4),MX,-1 f,knopen(ii+5),MX,-1 f,knopen(ii),MY,1 f,knopen(ii+1),MY,-1 f,knopen(ii+4),MY,1 f,knopen(ii+5),MY,-1 SOLVE SAVE /POST1 *DIM,disprx%ii%,ARRAY,4,1 *DIM,dispry%ii%,ARRAY,4,1 *GET,disprx%ii%(1),node,knopen(ii),rot,x *GET,disprx%ii%(2),node,knopen(ii+1),rot,x *GET,disprx%ii%(3),node,knopen(ii+4),rot,x *GET,disprx%ii%(4),node,knopen(ii+5),rot,x *GET,dispry%ii%(1),node,knopen(ii),rot,y *GET,dispry%ii%(2),node,knopen(ii+1),rot,y *GET,dispry%ii%(3),node,knopen(ii+4),rot,y *GET,dispry%ii%(4),node,knopen(ii+5),rot,y *cfopen,disprx%ii%rotx,txt *vwrite,disprx%ii%(1) (E26.16) *cfclose *cfopen,dispry%ii%roty,txt *vwrite,dispry%ii%(1) (E26.16) *cfclose *enddo -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 61.56.5.92 ※ 文章網址: http://www.ptt.cc/bbs/Cad_Cae/M.1399297508.A.0B2.html