[問題] command-line argument
開發平台: dev c++
我的command為 "123.exe input.txt output.txt"
如果argc!=3 代表出錯了,可是我的argc一直為4
檢查argv發現
argv[0]=E:\user\123.exe <---多抓了一個command
argv[1]=123.exe
argv[2]=input.txt
argv[3]=output.txt
正確的應該是
argv[0]=123.exe
argv[1]=input.txt
argv[2]=output.txt
之前似乎都正常,不知道改到了什麼就爛掉了
int main (int argc, char *argv[])
{
if (argc != 3)
{
printf("The correct format is: ID.exe infile outfile\n");
for (int i=0;i<argc;i++)
{
printf("argv[%d]=%s\n",i,argv[i]);
}
system("pause");
exit(1);
}
fr=fopen(argv[1], "r");
fw=fopen(argv[2], "w");
....
}
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 140.113.249.109
→
01/20 11:30, , 1F
01/20 11:30, 1F
→
01/20 11:33, , 2F
01/20 11:33, 2F
→
01/20 11:36, , 3F
01/20 11:36, 3F
→
01/20 11:37, , 4F
01/20 11:37, 4F
→
01/20 13:47, , 5F
01/20 13:47, 5F
→
01/20 13:52, , 6F
01/20 13:52, 6F
C_and_CPP 近期熱門文章
PTT數位生活區 即時熱門文章