[問題] 下列程式能印出圓周率達800位,將各for loops改成while loop

看板C_and_CPP (C/C++)作者 (豬)時間16年前 (2009/04/07 13:55), 編輯推噓1(103)
留言4則, 3人參與, 最新討論串1/1
這是老師上課出的作業, 下列程式能印出圓周率達800位,將各for loops改成while loops: long a=10000, b, c=2800, d, e, f[2801], g; main() { for( ; b-c ; ) f[b++] = a/5; for ( ; d = 0, g = c*2; c -= 14, printf("%.4d", e+d/a), e = d%a) for (b = c; d += f[b]*a, f[b] = d%--g, d /= g--, --b; d *= b); } 看不懂寫法,改成while也沒成功跑出來,請問有人會嗎? 此程式跑出來的結果如下 31415926535897932384626433832795028841971693993751058209749445923078164062862089 98628034825342117067982148086513282306647093844609550582231725359408128481117450 28410270193852110555964462294895493038196442881097566593344612847564823378678316 52712019091456485669234603486104543266482133936072602491412737245870066063155881 74881520920962829254091715364367892590360011330530548820466521384146951941511609 43305727036575959195309218611738193261179310511854807446237996274956735188575272 48912279381830119491298336733624406566430860213949463952247371907021798609437027 70539217176293176752384674818467669405132000568127145263560827785771342757789609 17363717872146844090122495343014654958537105079227968925892354201995611212902196 08640344181598136297747713099605187072113499999983729780499510597317328160963185 請按任意鍵繼續 . . . -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.230.221.74

04/07 14:10, , 1F
1.先code排個版再貼吧~_~ 2.for->while其實不複雜的code
04/07 14:10, 1F

04/07 14:11, , 2F
只要注意 a.初始化index, b.邊界判斷, c.step值就能改了
04/07 14:11, 2F

04/07 15:05, , 3F
這對新手的確不容易,因為看不懂哪裡在判斷…
04/07 15:05, 3F

04/07 15:21, , 4F
感謝推文,問題解決了
04/07 15:21, 4F
文章代碼(AID): #19skg-Kq (C_and_CPP)
文章代碼(AID): #19skg-Kq (C_and_CPP)