[問題] 關於POST該輸入的參數

看板C_Sharp (C#)作者senjor (哞哞)時間18年前 (2007/06/30 17:57)推噓3(3推 0噓 3→)

留言6則, 3人參與討論串1/1

小弟今天要對一個網頁傳送POST 利用fiddler抓到TEXTVIEW如下 -----------------------------7d719c1f806fa Content-Disposition: form-data; name="configfile" /usr/opt/www/pub/CBS/services/NetPhos-2.0/NetPhos.cf -----------------------------7d719c1f806fa Content-Disposition: form-data; name="SEQPASTE" <KLVDTANFDDYMKALGVGFATRQMAGLTKEISFKLDEEFDETTADDRHVKKLILTLTMGNVVSTRTYPTTI -----------------------------7d719c1f806fa Content-Disposition: form-data; name="SEQSUB"; filename="" Content-Type: application/octet-stream 那我程式碼如下 HttpWebRequest myHttpWebRequest = (HttpWebRequest)WebRequest.Create("http://www.cbs.dtu.dk/services/NetPhos/"); myHttpWebRequest.Method = "POST"; string postData = "-----------------------------7d732224806fa\nContent-Disposition: form-data; name=\"configfile\"\n\n/usr/opt/www/pub/CBS/services/NetPhos-2.0/NetPhos.cf\n-----------------------------7d732224806fa\nContent-Disposition: form-data; name=\"SEQPASTE\"\n<KLVDTANFDDYMKALGVGFATRQMAGLTKEISFKLDEEFDETTADDRHVKKLILTLTMGNVVSTRTYPTTI\n-----------------------------7d732224806fa\nContent-Disposition: form-data; name=\"SEQSUB\"; filename=\"\"\nContent-Type: application/octet-stream"; ASCIIEncoding encoding = new ASCIIEncoding(); byte[] byte1 = encoding.GetBytes(postData); myHttpWebRequest.ContentType = "multipart/form-data"; myHttpWebRequest.ContentLength = byte1.Length; Stream newStream = myHttpWebRequest.GetRequestStream(); newStream.Write(byte1, 0, byte1.Length); MessageBox.Show("The value of 'ContentLength' property after sending the data is "+ myHttpWebRequest.ContentLength); newStream.Close(); HttpWebResponse myResp = (HttpWebResponse)myHttpWebRequest.GetResponse(); StreamReader myReader = new StreamReader(myResp.GetResponseStream()); webBrowser1.DocumentText = myReader.ReadToEnd(); 其實我不確定的是 POSTDATA裡面到底要裝什麼要怎麼表達我要傳送的變數名稱跟內容呢 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 210.70.85.138